A CIRCUIT FOR CONTROLLING MOTOR SPEED

PROBLEM STATEMENT

The main problem of this milling machine is when the grains is finished and the operator wants to put another for another product then the motor is still rotating in the same speed as before (no load speed is equal to full load speed).
Due to this problem, designing of a circuit for controlling speed of the motor will be done.


OBJECTIVES

To minimize cost of electricity by designing a circuit for controlling motor speed.

SIGNIFICANT OF THE PROJECT

To minimize cost of electricity.
It will reduce motor overheating.
To improve efficiency of the machine.

LITERATURE REVIEW

Literature review include existing system and proposed system.

EXISTING SYSTEM

DISADVANTAGE OF EXISTING SYSTEM

When there is no load in the machine then the motor is still rotating in the same speed as it was before.

PROPOSED SYSTEM

The following are data collected from the field of study
Thermal overload protection
3phase miniature circuit breaker
Cartridge fuses 100A
Motor ratings
Motor rated voltage –380 — 400V
Rated power – 7.5kW/10HP
Current taken – 17.7A full load
Motor speed – 1450RPM
Motor type – AC Three phase Induction motor
Contactor size – 220V AC coil voltage
Power factor – 0.87
Frequency – 50Hz
Connection – Direct on line (DOL)
Size of cable in control circuit 2.5mm2

Analysis of the motor

Specification of the motor
Rated power = 7,5 kW/10HP
Current taken 16.7A
Power factor (cos ɵ) = 0.87
Motor full load speed = 1450 rpm

Therefore,

Full load line current =HP × 0.746 × [1000 ÷ (1.732 × V)]
= 10 × 0.746 × [1000 ÷ (1.732 × 415)
= 10.4A
Full load phase current = line current ÷ 1.732
= 10.4 ÷ 1.732
= 5.9A

Rated torque

Tfl =5252×HP×rpm

But for motor less than 30kW

Starting torque =3×Ifl

                                     =3×16.7A

                         =50.1Nm

Torque developed

            T= (applied voltage)2

                   T=V12

Transformer selection

Then the capacity of Autotransformer to be connected in the motor is as follows
Motor rated = 10HP/7.5Kw
Voltage applied = 415V
Current = 16.7A
Speed = 1450rpm
So Current at instant of starting (Iis) takes 5 to 7 full load line current
Iis = 5×16.7A
Iis = 83.5A

But according to the tapping of autotransformer 65% tapping would reduce the Iis to 42% of Iis using full voltage starting

             That is  

                      Iis = 83.5A ×42%

                          = 35.07A

          Voltage during starting period Vs = 415V ×65%

                                                                = 269.75V

    Then kVA rating of autotransformer (S) is given by

                                          S = 1.732 × Iis ×Vs          

                                             = 1.732 × 83.5A × 269.75V

                                             = 16384.9 VA or 16.3849 kVA

But the available autotransformer to be used is of 20kVA  

 Analysis of motor starter

      Contactor sizing

Rated voltage=380V then

   Coil voltage= 220V ac

Coil resistance= 22ῼ

Then current taken by contactor

                   I=V/R

                     =220V/22ῼ

                      =10A

Overload relay 

Thermal overload relay setting = 100% × full load current (line)
= 1 × 10.4AS
= 10.4A

therefore
Minimum setting=70% ×full load current (phase)
=70% × 5.9A
=4.13A
then Maximum setting = 120% × full load current(phase)
= 120% × 5.9A
=7.08A

Start and stop push button
=10A

Fuse selection
From the table above Therefore,
Maximum size of time delay fuse
= 300% × line Ifl
=3 × 10.4
= 31.2A

then
Maximum size of non-time delay fuse
=175% × line Ifl
= 1.75 × 10.4
=18.2A

Size of Circuit breaker

       Therefore From NEC 430-52 table

 Maximum size of instantaneous trip circuit breaker

          =800% × line Ifl

               = 8 × 10.4A

          =83.2A

 Then Maximum size of inverse trip circuit breaker

          =250% × line Ifl

          =2.5 × 10.4A

          =26A

ADVANTAGES OF PROPOSED SYSTEM

The efficiency of the machine will be improved
It will reduce the cost of electricity

CONCLUSION

From the result of the circuit above, so it’s conclusion that the proposed system diagram of the project is working properly and it can be implemented / build into the circuit board ready for use. But the main obstacle is the availability of autotransformer components which is difficult for me to get in the market. Also the designed system meets the objectives of the project in several percentages i.e. to increase efficiency and reduce overheating of the particular machine.

RECOMMENDATION

Most of the milling machine do not use this method of speed control therefore, the company should use this method because it is very economic to the environment so as to improve the efficiency of the machine and avoid some cost which can be occur due to overloading or overheating of the motor.

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